Operator Precedence

operator-precedence.pde
/**
 * Operator Precedence
 * 
 * If you don't direction state the order in which an 
 * expression is evaluated, it is decided by the operator 
 * precedence. For example, in the expression 4+2*8, the 
 * 2 will first be multiplied by 8 and then the result will 
 * be added to 4. This is because multiplication has a higher 
 * precedence than addition. To avoid ambiguity in reading 
 * the program, it is recommended to write the expression as 
 * 4+(2*8). The order of evaluation can be controlled through 
 * adding parenthesis in the code. 
 */

// The highest precedence is at the top of the list and 
// the lowest is at the bottom.
// Multiplicative: * / %
// Additive: + -
// Relational: < > <= >=
// Equality: == !=
// Logical AND: &&
// Logical OR: ||
// Assignment: = += -= *= /= %=

size(640, 360);
background(51);
noFill();
stroke(51);

stroke(204);
for (int i = 0; i < width - 20; i += 4) {
  // The 30 is added to 70 and then evaluated
  // if it is greater than the current value of "i"
  // For clarity, write as "if (i > (30 + 70)) {"
  if (i > (30 + 70)) {
    line(i, 0, i, 50);
  }
}

stroke(255);
// The 2 is multiplied by the 8 and the result is added to the 4
// For clarity, write as "rect(5 + (2 * 8), 0, 90, 20);"
rect(4 + (2 * 8), 52, 290, 48);
rect((4 + 2) * 8, 100, 290, 49);
  
stroke(153);
for (int i = 0; i < width; i += 2) {
  // The relational statements are evaluated 
  // first, and then the logical AND statements and 
  // finally the logical OR. For clarity, write as:
  // "if(((i > 20) && (i < 50)) || ((i > 100) && (i < width-20))) {"
  if (((i > 20) && (i < 50)) || ((i > 100) && (i < width - 20))) {
    line(i, 151, i, height - 1);
  } 
}